# Find product of the oxidation of 2-methylnaphthalene with chromium trioxide

This is a question from an organic chemistry book. I did not understand the solution given in that book. Here's the solution given in that book,

I know that CrO3 oxidizes methyl group of toluene, but here
Why are alpha positions more reactive and alpha positions of which functional group have they mentioned?

2) Why is the alpha position more reactive than the methyl group? This question of reactivity is tricky because other oxidants and reaction conditions will indeed oxidize 2-methylnaphthalene into 2-naphthoic acid. In general, electron-rich naphthalenes are able to oxidize into naphthoquinones, even just by exposure to $\ce{O2}$. If we assume (big assumption!!!) that these reactions to go through radical mechanisms, then we are either oxidizing the naphthalene pi system (left) or abstracting an H* (right). There's various arguments to be made about which pathway is more stable based on the extent of conjugation, and obviously that will depend on the reagent and solvents in use as well.