Branched chain molecules have lower boiling point than straight chain molecules because branched chain molecules have a smaller surface area where they can be attracted by other molecules. Then, why Isodecane (a branched chain molecule) has a higher boiling point than Decane (a straight chain molecule)?
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If you mean 2-methylnonane with isodecane, your data is wrong.
2-methylnonane has a boiling point around 166 °C, which would support the rule of thumb that you mentioned.
answered Apr 8 '14 at 11:14
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1$\begingroup$ :I am grateful to you. Actually this was the boiling point of isodecane given in my textbook. Now, I have come to know that the given information is wrong. $\endgroup$ – azaidi Apr 8 '14 at 11:32
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The only problem here is the units - the boiling point of isodecane is given in Fahrenheit and the boiling point of decane in Celsius.
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$\begingroup$ Your answer has been flagged as low quality, which was disputed, but nevertheless you might want to expand your future answers a little more in order to avoid this. How to Answer gives a short, helpful introduction. $\endgroup$ – Martin - マーチン♦ Sep 7 '15 at 10:17
