$15~ \textrm{mL}$ of $4 ~\textrm{N}$ hydrochloric acid, $ 25~ \textrm{mL}$ of $2~ \textrm{M}$ $\textrm{H}_3\textrm{PO}_3$ and a certain volume of $2.5~\textrm{M}$ sulphuric acid are mixed together and made upto $2 ~\textrm{L}$.
$30~ \textrm{mL}$ of this acidic mixture exactly neutralises $42.9~\textrm{mL}$ of a sodium carbonate solution which contains $0.1~ \textrm{g}$ of sodium carbonate decahydrate in $10 ~\textrm{mL}$ of solution. The volume of $\textrm{H}_2\textrm{SO}_4$ added is?
I calculated the number of gram equivalents of sodium carbonate and thus calculated the normality of the acidic solution required.
I am having trouble with the statement "is made up to", so I'm assuming that this means that the solution is diluted with water to make a volume of 2 litres.
This seems to be yielding a negative volume. Can you tell me what I'm doing wrong?