# Plotting a calibration curve for Gas-Liquid Chromatography

Question:

The given graph of abundance of different samples of butanol with respect to time is- Textbook solution: But why aren't the points like this:

$$(20,5);(40,10);(60,15);(a,7)$$

after which, to plot the curve we can use $$y=mx+c$$ and then find the value of $$a$$?

• I get (60,16) for the third peak.
– LDC3
Oct 5 '14 at 4:59
• It's (40,11) in graph. Oct 5 '14 at 5:00
• @hey, no the numbers are not on the correct lines.
– LDC3
Oct 5 '14 at 5:02
• @LDC3 Oh ok i see! Oct 5 '14 at 5:05

If I remember correctly, the amount of your compound isn't proportional to the peak height but to the peak area.

Back in the days, when plotters were just plotters (=no numerical integration of the peaks), people used to cut out the curves and weighted the paper pieces on a balance to determine the peak area.

• I still do that!
– user8016
Oct 5 '14 at 4:46
• If you have sharp, narrow peaks, the height is a good substitute for the area. But the area is more accurate.
– LDC3
Oct 5 '14 at 5:01

You are actually correct, the formatting of the vertical axis in the solution graph has resulted in the vertical (Peak Height) values written below the actually gridline it is referring to - you can see the same for peak height values of 5, 10 and 15.

Using the linear equation formula $y=mx+c$ for the 3 known values yields a relationship of:

$$P = 0.25C$$

(Where $P$ is Peak height and $C$ is concentration)

Substituting the known peak height for the 4th value:

$$7=0.25C$$

$$C=28$$

Which is exactly where it is shown on the graph in the answer.