5
$\begingroup$

Numerous internet sources (1, 2, 3, etc.) state this fact, including a Wiley publication "Alkaline Earth Metals: Inorganic Chemistry - William S. Rees Jr" (DOI: 10.1002/0470862106.ia005) on page 9:

The bicarbonates of group 2 elements are stable only in solution.

Why is it so? Why do solid alkaline earth metal bicarbonates decompose/are unstable?

In other words, (thanks Zhe!), group 1 bicarbonates are stable. Group 2 bicarbonates are not. They decompose into the group 2 carbonate, water, and carbon dioxide. What is the principle difference between group 1 and group 2 bicarbonates that leads to a thermodynamic preference for the carbonate in one case and the bicarbonate in the other? Also, why is the preference only shown in the solid state, but not in the aqueous state?


I am not asking about thermal stability. I am just asking that what's the problem if we take these bicarbonates in solid state at room temperature and leave them there. Why would they decompose?

$\endgroup$
2
1
$\begingroup$

The unstability of alkaline earth bicarbonates can be traced back to their hypothetical crystal structure. Let us start with calcite CaCO3. There, each Ca2+ cation coordinate with 6 oxygen atoms in an octahedral shape. Besides, each oxygen coordinate with a C and two metal atoms. Thus, each carbonate group (containing three oxygens) coordinate with six metal atoms (valence 2+) without much distortion, creating a structure that is very stable.

Carbonate Structure

Now, the bicarbonate structure is a distortion of CaCO3. There, on oxygen atom coordinates with three metals, another with two metals, and another with one metal plus a hydrogen atom. The latter is stabilized via hydrogen bonding with an oxygen atom which is coordinated with two metals. On average, you still have 1 metal atom (valence 1+) for each HCO3- group. Besides, both anion and cation are still hexacoordinated.

Bicarbonate Structure

Li atoms are too small and can hardly be stabilized by coordinating with 6 oxygens. The anionic nature of such oxygens would make them "feel" and repel each other. This is the reason behind the instability of LiHCO3, previously mentioned by Oscar Lanzi.

Conversely, to create a solid bicarbonate of an alkaline earth metal, eg Ca(HCO3)2, each Ca atom would need to coordinate with 12 different oxygen atoms, which would be awfully unstable. Alternatively, each oxygen atom would need to "uncoordinate" with a metal atom, making them a lot less stabilized by electrostatic forces. In any case, the crystalline CaCO3 and their decomposition products (CO2, H2O) would be a more stable arrangement.

$\endgroup$
1
  • 1
    $\begingroup$ If there is a number with a plus or minus sign, it cannot be valence. Considering the context, it's either charge, or oxidation number. $\endgroup$
    – andselisk
    Jul 26 '21 at 15:10

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.