The compound in question is given below


This is one of several compounds that was listed in a JEE Advanced 2017 question about aromaticity. From the solutions it seems this compound is aromatic.

However this compound has 2 sp3 carbon atoms and there isnt conjugation either, so why is this compound aromatic?

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    $\begingroup$ Arguably, compounds can't be aromatic at all; individual rings can. $\endgroup$ May 17, 2018 at 9:45
  • $\begingroup$ If thats the case how would compounds like Pyrene be aromatic? From what i understad if the rings are attached via bonds like in Biphenyl or in triptycene, it must be considered single cycle at a time. But in fused ring systems like anthracene, napthalene, we consider them together. Hence the question. Please correct me if Im wrong. $\endgroup$ May 17, 2018 at 9:54
  • 2
    $\begingroup$ You're right. The 4n+2 rule was only made for monocyclic ring systems. for other types of compounds, it may not be necessarily correct. Also see Is pyrene aromatic? $\endgroup$ May 17, 2018 at 10:01
  • $\begingroup$ I know how pyrene is aromatic, I just mentioned that to say that we need not always look single ring at a time. $\endgroup$ May 17, 2018 at 10:02
  • $\begingroup$ @ULTIMATEGAMER07 Consider if there weren't the whole other ring, but just a benzene ring bound to an ethene. Would the benzene ring still be aromatic? $\endgroup$
    – Tyberius
    May 17, 2018 at 13:11

1 Answer 1


The compound is aromatic, it can be regarded as a modified styrene which in turn is a benzene derivative.

The compound contains a cyclic pi system which has 4n+2 pi electrons and is planar. Thus it is aromatic. It is normal not to count the pi electrons in side groups when counting the pi electrons in possible aromatic compounds.

For example benzoic acid has a carboxylic acid which has 2 pi electrons in it, these are not added to the total of the pi electrons in the benzene ring despite the fact that the benzene ring and the carboxylic acid can become coplanar thus allowing the pi systems of the two to overlap and join into a larger system.

If we consider naphthalene then this is a compound which has ring of ten carbons, half way around the ring there is a sigma bond which links one side of the ring to the other. Thus it can appear that naphthalene has two rings.

When we consider aromatic systems we should ignore sigma bonds, the sigma bonds may help to hold the molecule together but the sigma bonds which are within the nodal plane between the two sides of the pi system are unable to take part in the pi system.

We should be careful of the lone pair which I lightheartedly describe as "the bond to nowhere". In some aromatic compounds such as indole and thiophene one of the lone pairs on the heteroatom starts off in an atomic orbital which is a p orbital which then takes part in the pi system of the aromatic ring.

In other heterocycles such as pyridine the lone pair is in the nodal plane where the angular function of the wavefunctions of all the atomic orbitals which make up the pi system is zero. Thus there is no orbital overlap between the lone pair of a pyridine nitrogen and the pi system of the pyridine.

Be careful as in some cases such as pyrazole and oxazole there are both heteroatoms which contribute lone pairs to the pi system and other heteroatoms which only contribute a single electron (rather than a lone pair) to the pi system.

  • $\begingroup$ I am down-voting this, because it needlessly oversimplifies aromaticity. The compound itself is not aromatic, the phenyl ring is an aromatic subsystem. The application of Hückel's rules is also borderline correct here. $\endgroup$ Jun 13, 2018 at 7:49

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