Why is the reverse electron demand Diels-Alder reaction much rarer than the normal one? By reverse electron demand, I mean one with an electron-rich dienophile and an electron deficient diene.

In the book by Clayden they have drawn a diagram with the electron deficient dienophile lower in energy and saying that it would prefer to give its LUMO to the reaction.

But, I don't get what's wrong with an electron-rich dienophile lending its HOMO.

  • $\begingroup$ I was just reading about this very thing... Hope this helps: en.m.wikipedia.org/wiki/… $\endgroup$
    – Abhigyan
    May 11, 2018 at 13:13
  • 1
    $\begingroup$ Thanks. so if i'm not wrong normal and inverse DA are essentially the same thing except that if the energy of the FMO of the diene is greater than the dienophile then theinverse dominates and if it is lower then the normal pathway dominates.. $\endgroup$
    – DHYEY
    May 14, 2018 at 17:14
  • $\begingroup$ But still i am confused as to why are there remarkably fewer examples of inverse as compared to normal DA or is it just a coincidence.. $\endgroup$
    – DHYEY
    May 14, 2018 at 17:15
  • 1
    $\begingroup$ Maybe because the energy difference between diene HOMO and dienophile LUMO is on average lower than the difference in energy between dienophile HOMO and diene LUMO. $\endgroup$
    – EJC
    May 26, 2018 at 17:52

2 Answers 2


Inverse electron demand reactions are inefficient and slow. Even the prototypical Diels-Alder reaction of 1,3-butadiene and ethylene is quite sluggish. From here you can see the reaction only proceeds to 93.5% yield when ran with ethylene in excess by 50:1 at 200ºC and 350 atm for 4 hours. Yikes!

Now consider that some normal electron demand D-A reactions can occur at room temperature. In fact, 1,3-butadiene spontaneously dimerizes to 4-vinylcyclohexene while in storage, meaning the dimer must be cracked by heating immediately before use. This should give you an idea of the sensitivity of D-A reactions to substituent groups. By lowering the HOMO-LUMO gap, orbital overlap is improved, lowering the activation energy and resulting in a faster reaction.

To supplement and support my answer, here is a paraphrased excerpt from Modern Physical Organic Chemistry by Anslyn and Dougherty (2006):

Electron-withdrawing groups on the dienophile lower its LUMO. This occurs because electronegative substituents have correspondingly lower energy MOs, and lower the energies of all MOs in which they participate. Inversely, electron-donating groups raise the diene MOs.

DA Relative MOs

In support of this analysis, the log($k$) for Diels-Alder reactions correlate quite well with the inverse of the difference in energy between the ionization potential of the diene (related to the energy of the HOMO) and the electron affinity of the dienophile (related to the energy of the LUMO). To further enhance the electrophilicity of the dienophile, it is common to add Lewis acids that can complex the electron withdrawing groups on the dienophile, further lowering the LUMO.

  • $\begingroup$ This seems to assume that the rates go in the order normal electron demand > no electronic bias > inverse electron demand, however, I’m curious as to exactly what point the inverse electron demand starts to be faster than reactions with no electronic bias. There has to be some point at which the diene LUMO is so high and the dienophile HOMO so low that that frontier orbits interaction becomes more important than the usual diene HOMO + dienophile LUMO, or am I wrong? $\endgroup$ May 30, 2018 at 8:52

In order to understand why the HOMO of the dienophile is less easily donated, let us again understand the original Diels-Alder properly.

In the original Diels-Alder reaction, there is a close similarity in the energies of the HOMO of the diene and the LUMO of the dienophile. As a result, they form the strongest orbital interactions. The presence of electron releasing groups on the diene and electron withdrawing groups on the dienophile essentially reduce this energy difference even further.

Moving on to the inverse electron-demand Diels-Alder: here, the LUMO of the diene and the HOMO of the dienophile are closest in terms of their energies. Because of this, they form the strongest orbital interactions now, and hence this reaction is able to take place.

As you might have already guessed, the chances of there being a close similarity in the energies of the LUMO of the diene and the HOMO of the dienophile is much less compared to the normal Diels-Alder case. Because of this, we have a greater number of reagents that can undergo the normal Diels-Alder than the inverse one. It's just a question of its rarity than its feasibility, because now you're looking for an electron deficient diene and an electron rich dienophile. In general, due to the resonance stabilisation in dienes, there's a good deal more electron rich dienes than deficient ones, and vice versa for the dienophiles...

I hope that this answers your question.

  • $\begingroup$ Also, @Marko 's comment really sums it up: > Maybe because the energy difference between diene HOMO and dienophile LUMO is on average lower than the difference in energy between dienophile HOMO and diene LUMO. $\endgroup$
    – Abhigyan
    May 28, 2018 at 17:34
  • $\begingroup$ There are perfectly synchronous iedDA reaction as far as we know and there are asynchronous normal demand DA reactions. This is not a special feature of either type as well as the concerted mechanism, there are (ied)DA reactions which (might) proceed by two step mechanisms $\endgroup$
    – DSVA
    May 29, 2018 at 8:06

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.