Arrange the following in decreasing order of basicity:
- $\ce{N(CH3)3}$
- Guanidine
- $\ce{N(C6H5)3}$
- $\ce{NH(CH3)2}$
My answer - 2 > 1 > 4 > 3
Option '2' due to equivalent resonance structures on protonation. Then option '1' due to thrice +I effect. Followed by option '4' having +I effect twice which causes the lone pair electrons to be repelled from the nitrogen atom. Finally option '3', because lone pair electrons are delocalised on three rings.
Is my logic for the question correct or not? I am not sure if my answer is correct.