4
$\begingroup$

This is a follow-up to the question here. There is no mono-anionic stage shown, does it "disproportionate" to the neutral molecule and the di-anion?

$\endgroup$
  • 3
    $\begingroup$ It just means second pKa is not significantly higher then first. $\endgroup$ – Mithoron May 4 '18 at 22:49
  • 1
    $\begingroup$ So maybe when we form the mono-anion the conjugation of the two phenolic rings favors driving the next proton off to form a highly stabilized "quinone-aromatic" structure, thus lowering that pKa? $\endgroup$ – Oscar Lanzi May 5 '18 at 0:55

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.