# Hydroboration oxidation reaction on trans,trans,trans-1,5,9-cyclododecatriene with carbon monoxide

The given solution:

I got this question in an entrance exam coaching test paper in India. Product P is easily covered by the mechanism of simple hydroboration-oxidation reaction, and I've understood it well. However, product Q is what intrigues me.

Looking at the product and the reactants, I can guess that the carbon in $\ce{CO}$ functions as the source for the bridging carbon in the product Q. However, I could not figure out the mechanism for the same. It is not given in my textbook, and wasn't found via Google searches either.

I'v well understood how the intermediate product (bridged by boron) had formed. However, how is the carbon monoxide supposed to displace boron from there? I can guess that once a carbonyl group bridge is formed in the middle, the alkaline hydrogen peroxide will reduce the ketone to an alcohol (to get product Q), but I am not too sure.

• What's the stereochemistry of the final product? (One containing 3 -OH groups) – arya_stark Jul 12 '18 at 15:29
• @schrodinger_16 You may look at the hydroboration-oxidation mechanism for that - which I've since forgotten. The stereochemistry was not mentioned in the question. – Gaurang Tandon Jul 12 '18 at 16:11
• My instructor told me that only two OH groups are on the same side in the final product, and I've been wondering why ever since then. – arya_stark Jul 12 '18 at 16:32
• @schrodinger_16 I'm afraid I actually don't know the stereochemistry. – Gaurang Tandon Jul 12 '18 at 17:04