# What is the lewis structure of NO [duplicate]

I am a bit confused about the lewis structure of $\ce{NO}$ The answer from my worksheet is $\ce{N=O}$ with nitrogen having a free radical. But I drew the structure as N triple bonded to $\ce{O (:N#O:)}$ and oxygen has the free radical. I am confused as to why my answer is not the case

• You'd get more then 8 electrons on N. – Mithoron May 2 '18 at 0:09
• It's always a good idea to check formal charges. In N=O, the formal charge is zero on each atom. In N triple bonded to O with a single electron on N, the formal charge is 1 and -1 on the N and O respectively. Thus, N double bonded to O is correct. – Dr. J. Jun 1 '18 at 10:34
• – mykhal Jul 31 '18 at 14:37