# Effusion rate 1.4 times faster SO2(g)

How do I solve this- Which diatomic gas would effuse at a rate that is 1.4 times faster than the rate at which so2(g) effuses at any given temperature? This is high school chemistry.

I did: (using graham's law) 1.4= sqroot of 64gmol-1 / xgmol-1 => 1.96= 64/x => 1.96x=64 => x=32.65g/mol. 32.65/2 (bc its a diatom) => 16.325g/mol which is close to oxygen. At first, I found Urms of SO2 using 273k for T, 0.064kg for M and 8.314 for R, I got 326. Then multiplied that by 1.4 and got 456. Then I put 456/326= sqroot of 64gmol-1/ xgmol-1 and solved for x. I realized the 456/326 equaled 1.4, so I figured I didn't need to find Urms in the first place.

• See Graham's law of effusion – Frank Apr 25 '18 at 22:12
• would O2 be the correct answer? – Chrissy Apr 25 '18 at 22:31
• This is a homework question. We have a policy which states that ‎you should show your thoughts and/or efforts into solving the problem. It'll make us certain that ‎we aren't doing your homework for you. Otherwise, this question may get closed.‎ Please edit in your full reasoning or thoughts on this. – airhuff Apr 25 '18 at 22:36
• @Chrissy we will tell you whether oxygen is correct if you tell us how you arrived at that possibility. – Oscar Lanzi Apr 25 '18 at 22:49
• @OscarLanzi sorry didn't know about the policy. I updated the post. – Chrissy Apr 25 '18 at 23:13