Which is more conducting - molten sodium chloride or molten magnesium chloride?

I'm pretty sure I know the answer to this but my problem is putting into words. Magnesium is more conductive due to its 2+ charge, and the $\ce{NaCl}$ having a neutral charge. Right?

Would I be right in saying that as the compounds are heating up and melting the ions break away from each other and the ratio of ions in $\ce{MgCl2}$ is 2:1 so therefore the solution would be more highly charged than that of the $\ce{NaCl}$?

I know I'm on the right track, just struggling to explain it.


closed as unclear what you're asking by Tyberius, Mithoron, aventurin, Jon Custer, Todd Minehardt Apr 25 '18 at 16:04

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • 2
    $\begingroup$ The solution is not charged; it is neutral, since it contains equally many positive and negative charges. Also, you don't have any solution at all. Other than that, you may or may not be right. True, $\ce{Mg^2+}$ has greater charge than $\ce{Na+}$, so what? $\endgroup$ – Ivan Neretin Apr 23 '18 at 8:22

Browse other questions tagged or ask your own question.