# Protonating/basic site and Brønsted basicity orders of beta, gamma, and delta lactams

Consider the three cyclic amides:

1. $\beta$-lactam
2. $\gamma$-lactam
3. $\delta$-lactam

### My question

What is the basic site (site of protonation) for these three lactams? And what should be their Brønsted basicity order?

### My approach

If you consider $\ce{O}$ as the protonating site for the lactams ($\ce{O}$ can act as the basic site as the lone pair on $\ce{N}$ is delocalising with the carbonyl carbon, which increases electron density on $\ce{O}$, which helps to donate its lone pair to $\ce{H+}$, and after forming the conjugate acid, its resonance stabilisation is still there, which can be lost if it gets protonated through $\ce{N}$ (due to non availablity of lone pair). Delocalisation is not at all possible in $\beta$-lactams, due to huge angle strain. But $\delta$-lactam is the ideal situation for delocalisation which will increase the electron density on $\ce{O}$ atom, and hence will be the most basic due to the most availability of electron density of $\ce{O}$. So, basicity order will be $$\ce{\delta-lactam > \gamma-lactam > \beta-lactam (considering O as the protonating site)}$$

But if you consider N as the protonating site for these lactams, the delocalisation actually decreases the basicity, as delocalisation induces non-availability of electrons on $\ce{N}$ atom.

Going by this logic , basicity order should be, $$\ce{\beta-lactam > \gamma-lactam > \delta-lactam (considering N as protonating site)}$$

So, these two logics contradict each other and hence I am unable to decide the protonating sites for amides, as in some cases $\ce{N}$ is seen to be protonating site, and in some cases $\ce{O}$. Can anyone explain what should be the proper logic to deduce the Brønsted basicity of these lactams?

• Small tip: Before focusing on cyclic amides, focus on a simple amide. We are asking ourselves which site is basic and which one is acidic. Try writing the resonance structure of a simple R-CO-NR2 system. We know that an amine nitrogen is basic since it has a readily available electron pair to share. In the resonance structure that you wrote, what happened to the electron pair of that amide nitrogen? Now, try writing the two hypotheses (protonated O vs protonated N) and their resonance structures. What do you see? – The_Vinz Mar 26 '18 at 18:50
• @The_Vinz I think his question is fair. He is aware of the resonance, but he is looking at the cases where the resonance is not possible due to torsional impediments of the ring strain. $\beta$-lactams are not planar, thus there is little, if any, delocalization of the nitrogen lone pair into the carbonyl (which is another reason why they are susceptible to hydrolysis). – ralk912 Mar 27 '18 at 1:56