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This question already has an answer here:

So I am battling with the last part of this transformation and was hoping someone could explain this mechanism to me so that I can confirm my answer.

Treating an alcohol with a strong hydrohalic acid results in the formation of alkyl halide and proceeds through an SN1 mechanism. (Protonation of alcohol on the carboxylic acid, then loss of $\ce{H2O}$ to form a carbocation) But $\ce{HCl}$ is supposed to give a substitution reaction and not an elimination reaction. So I am unsure how the final product is formed.

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marked as duplicate by Mithoron, Gaurang Tandon, Todd Minehardt, Community Mar 24 '18 at 7:06

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

  • $\begingroup$ Looking at the product, we can see there's a decarboxylation here due to the "heat". I bet the $\ce{HCl}$ is only to perform acidic cleavage of the epoxide. Though I am unsure how to knit both of them together. $\endgroup$ – Gaurang Tandon Mar 23 '18 at 11:34
  • $\begingroup$ Previously addressed. chemistry.stackexchange.com/questions/86726/… $\endgroup$ – user55119 Mar 23 '18 at 15:24