1
$\begingroup$

I think I'm doing it correctly but perhaps I'm missing something? Do they both need to be protonated enter image description here

$\endgroup$
3
  • $\begingroup$ i don't think they are both protonated because I tried that and it still came out to be wrong? $\endgroup$ – Harry Johnson Mar 22 '14 at 22:04
  • 1
    $\begingroup$ You were missing something, but your comment shows that you're thinking in the right direction! $\endgroup$ – Klaus-Dieter Warzecha Mar 22 '14 at 22:27
  • $\begingroup$ @KlausWarzecha I let the carboxylic be a salt and put in NH3CH3(+) and it still is wrong? What am I doing wrong ? $\endgroup$ – Harry Johnson Mar 22 '14 at 22:33
2
$\begingroup$

We agree that the amide is cleaved :)

Is it conceivable that methylamine, which is a gas under standard conditions, exists as methylammonium chloride here? ;)

$\ce{H3CCH2-CONHCH3 +HCl +H2O -> CH3CH2COOH + CH3NH3+Cl-}$

$\endgroup$
0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.