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If we look at the $\ce{ClO4-}$ anion, the chlorine atom in it is sp3 hybridised. Hence, it has a tetrahedral structure in which conjugation shouldn't be possible, but while explaining the acidic strength of $\ce{HClO4}$, I've seen many people claim that it is very acidic because the $\ce{ClO4-}$ anion is stable due to the conjugation of charge between the four oxygen atoms.

So, all of this boils down to: Is planarity really necessary for conjugation?

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this is a rather good question several students have actually asked me about it. it is not any exeption or contradiction .i have written the explanation below enter image description here

enter image description here

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    $\begingroup$ Could you type your answer out please? The content seems to be very nice. Thanks $\endgroup$ – Avnish Kabaj Apr 19 '18 at 8:06
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    $\begingroup$ I can't read that, please type it out. I would then even consider removing my down-vote. $\endgroup$ – Martin - マーチン Apr 25 '18 at 14:28

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