# What is the volume of the produced SO2 gas at STP? [closed]

In a electricity producing plant $3.1\times10^7\ \mathrm{kg}$ coal with $2.4\ \%$ rhombic sulfur is burnt every year. What is the volume of the produced $\ce{SO2}$ gas at STP?

My effort for solving this answer :

In one day how much sulfur is burnt. Then I wrote the equation

$$\ce{S + O2 -> SO2}$$

With the unitary method I tried but I am confused from where to start, how to start? Please give me a hint how to start the answer.

## closed as off-topic by Mithoron, airhuff, Todd Minehardt, Jon Custer, TyberiusMar 15 '18 at 22:36

This question appears to be off-topic. The users who voted to close gave this specific reason:

If this question can be reworded to fit the rules in the help center, please edit the question.

You have an excess of oxygen, right...?

So the limiting reactant is the sulfur, which is $2.4$% of the coal.

Spoiler: Step 1:

So calculate the sulfur content, which is $3.1 \times 10^7$ kilograms multiplied by $2.4 \times 10^{-2}$ which is $7.44 \times 10^5$ kilograms of sulfur.

Step 2:

The $\ce{SO_2}$ is $50$% sulfur by mass (32 amu of sulfur vs. 64 amu total) so there is $1.488 \times 10^6$ kilograms of $\ce{SO_2}$ produced.

Step 3 (for moles, optional):

If you want moles, divide by $64$, which is $2.325 \times 10^4$ moles (someone check my math)

Then again, you emphasized STP, so proceed with caution (sulfur doesn't react at $20$ degrees Celsius).

• Thanks , I have started to think your hint , soon I will get my answer :) – user70421 Mar 15 '18 at 18:37