1,2-Ethanediol, 1,2-diphenyl (also known as hydrobenzoin) can exist in three crystalline forms. One is S,S (formerly known as d or -), and its twin, R,R (formerly known as l or +), with a mp of 148-149 C; second is the meso form R,S (same as S,R), mp 139-140; and a third form, easily indicated as dl (or S,S:R,R), mp 122-123. It would be a eutectic.
Tartaric acid has the same kind of enantiomeric situation, but the racemic form (dl) is the highest melting form and the meso form is the lowest.
The formation of the low-melting dl form of diphenylethanediol suggests an intermolecular bonding which would likely be thru the hydroxide groups. So intramolecular bonding could give rise to one type of hydrogen bond while intermolecular bonding could lead to another type, with a different stretching frequency.
This is merely an expansion of the answer by ralk912.