Question
Write the half equations for the following reaction:
$$\ce{3OCl- -> 2Cl- + ClO3-}$$
I know that $\ce{Cl}$ is reduced from an oxidation state of 1+ to 1- (in $\ce{Cl-}$) and is oxidized from an oxidation state of 1+ to 5+ (in $\ce{ ClO3-}$)
Below is as far as I have gotten:
$$\ce{3OCl- -> ClO3- + 4e}$$ $$\ce{3OCl- + 6e -> 2Cl- }$$
I am sure this isn't correct, as I can't balance it and together they do not add up to the full equation