How do I calculate the number of moles of acetic acid present in 25 mL of a 10% vinegar solution?
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10% solution means 10 g of solute in 100 mL of the solution. So we have 10 g $\ce{CH3COOH}$ in 100 mL. Therefore , we have 2.5 g in 25 mL.
No. of moles of acetic acid = $\frac{m}{M}$
No. of moles = $\frac{2.5}{60}$ = 0.0417 moles of $\ce{CH3COOH}$.
