Is anyone familiar with a piece of equipment that can be purchased like a small burette? I need to find a way to dispense a liquid at a constant rate, however, the amount of liquid that I need to dispense will probably be less than 5 mL. A syringe is good in that regard, but it requires that I am able to push down with a constant pressure (which I doubt I can do). I've heard that they make burettes that are smaller (i.e around 25mL). Does anyone know if they make them smaller or at least not 2 feet long. Thank you for any useful information.
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$\begingroup$ How about a syringe pump? $\endgroup$ – Waylander Mar 1 '18 at 16:45
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$\begingroup$ Yes, a syringe pump would work. I forgot to mention that the amount of money I can spend is around 50-75 dollars which is much less than most syringe pumps. Thank you for your response. We are considering trying to build a make-shift syringe pump but are still not sure if they could be something else we could purchase that'd be better/faster to get. $\endgroup$ – Mflickin Mar 1 '18 at 16:50
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$\begingroup$ any old HPLC pump around? $\endgroup$ – DSVA Mar 1 '18 at 18:40
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The usual commercially available burettes are standardizes in the international standard ISO 385:2005 Laboratory glassware – Burettes. This standard includes small burettes with capacities of 1, 2, 5, 10 and 25 ml. The very small versions are typically advertised as “micro burettes”.
$$ \begin{array}{lllll} \hline \text{Nominal capacity} & \text{Graduation divisions} & \text{Accuracy limits} & & \text{Max. length}\\ & & \text{Class A and AS} & \text{Class B} \\ \mathrm{ml} & \mathrm{ml} & \pm\ \mathrm{ml} & \pm\ \mathrm{ml} & \mathrm{mm}\\ \hline 1 & 0.01 & 0.006 & 0.01 & 575 \\ 2 & 0.01 & 0.01 & 0.02 & 650 \\ 5 & 0.01 & 0.01 & 0.02 & 820 \\ 5 & 0.02 & 0.01 & 0.02 & 800 \\ 10 & 0.02 & 0.02 & 0.05 & 820 \\ 10 & 0.05 & 0.03 & 0.05 & 620 \\ 25 & 0.05 & 0.03 & 0.05 & 820 \\ 25 & 0.10 & 0.05 & 0.10 & 620 \\ 50 & 0.10 & 0.05 & 0.10 & 820 \\ 100 & 0.20 & 0.10 & 0.20 & 870 \\ \hline \end{array}$$
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$\begingroup$ @Mflickin you can accept the answer... $\endgroup$ – JavaScriptCoder Mar 1 '18 at 18:39
