Consider the reaction

$\ce{NH3 + H2O -> NH4+ + OH-}$

Here, $\ce{NH3}$ is a weak base, and thus $\ce{H2O}$ becomes a weak acid. Thus, shouldn't its conjugate be a strong acid? However, $\ce{NH4+}$ is a weak acid, instead of the strong conjugate acid it should be. Why is this?

  • $\begingroup$ I think you need to compare the strength of acid and base using the $pK_{a}$ values, it is not quantitative enough to just say 'strong' and 'weak'. $\endgroup$
    – bingung
    Mar 8, 2014 at 3:50
  • $\begingroup$ Please elaborate? I thought that if you had a weak acid or base it would produce a strong conjugate? Is that not the case? $\endgroup$
    – 1110101001
    Mar 8, 2014 at 4:17

1 Answer 1


Consider the $pK_b$ of the base $\ce{NH3}$ and the $pK_a$ of the acid $\ce{NH4+}$.

$pK_b$ = $4.8$

$pK_a$ = $9.2$

$\ce{NH3}$ is a stronger base than what $\ce{NH4+}$ is as an acid, being $4.8$ smaller than $9.2$: let's compare $pH$ for equal concentrations, say $0.1 M$.

For $\ce{NH3}$, you get $11.1$, while for $\ce{NH4+}$, you get $5.1$.

$11.1$ is about 100 times more "distant" from neutral $pH$ than $5.1$, if we move from the $pH$ scale to the concentration scale. That's what also stems from the comparison of the $pK$ values.

To simplify the problem, take the $pK_a$ for the acid/base couple, e.g. $\ce{NH4+/NH3}$, that is equal to $9.2$. If that value is larger than $7$, then, within that couple, the base will be stronger than its conjugated acid. The other way round, if $pK_a$ is lower than $7$.


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