Why does the starting compound not need an -OH group? I thought ozonolysis only produced carbonyls?
Add a comment
|
1 Answer
$\begingroup$
$\endgroup$
2
The product of ozonolysis depends on how you work up the intermediate ozonide. You are clearly familiar with the reductive workup (with dimethyl sulfide or PPh3) that gives two carbonyl compounds, aldehyde or ketone. But if you work up under oxidative conditions, as is the case here, you get carboxylic acids from mono-substituted double bonds and ketones from di-substituted.
-
$\begingroup$ Thank you! What do you mean by oxidative conditions? $\endgroup$ Feb 7, 2018 at 22:00
-
1$\begingroup$ Conditions that oxidise the ozonide, such as hydrogen peroxide as used here, chromate, permanganate or other oxidising agents. Any aldehyde formed would be oxidised to carboxylic acid under these conditions. Google 'Criegee Mechanism' for further information $\endgroup$ Feb 7, 2018 at 22:07