Grignard Reagent and Ester [closed]

Is this answer wrong? I feel like there should be a hydrogen instead of a carbon where I indicated in red. Thank you.

• A possible answer could have been (a) though, especially since they have not specified that the $\ce{MeMgBr}$ here is in excess. – Gaurang Tandon Feb 6 '18 at 8:06
• If e had a hydrogen there it would be the same structure as d. – Tyberius Feb 6 '18 at 18:34
• Where would the hydrogen come from? – Jan Feb 7 '18 at 1:27

The answer is correct. After the first nucleophilic attack from $\ce{MeMgBr}$, the ethoxy group left and the ester is transformed into a ketone (Step 2 in the link), then another $\ce{MeMgBr}$ attacks and introduce an extra methyl group, resulting in a $3^\circ$ alcohol after hydrolysis. The process is well described in this page.