SN1, SN2 or acid-base reaction

I am asked to give the type of reaction (SN1, SN2 or acid-base reaction) for the following reactions. I know that both $\ce{MeOH}$ and $\ce{EtOH}$ polar protic solvents, so because the first is an SN2 reaction shouldn't the second reaction be that as well? It says that it is an acid-base reaction as $\ce{MeO-}$ reacts with the $\ce{EtOH}$ to from 1-bromopropane, $\ce{MeOH}$ and $\ce{EtO-}$ and then goes on to from a SN2 reaction.

I would appreciate if someone could explain why the second reaction would be an acid-base reaction at first instead of a SN2 reaction.

• EtO- would be more basic than MeO-...the proton xfer is fast – Eashaan Godbole Apr 17 '18 at 15:38
• Note: $\ce{MeO-}$ is a strong base while, $\ce{EtOH}$ is a weak base. My question: how can you perform an acid-base neutralisation reaction then? + acid-base neutralistion also produces water as a product! – rv7 Jun 16 '18 at 15:42