# Products of the o-Toluidine oxidation with glucose oxidase and peroxidase

Could anybody describe which product is formed in the following reaction (o-Toluidine oxidation)?

$$\ce{H2O2 + o-Toluidine_{uncolored} - Peroxidase -> H2O + 1/2 O2 + o-Toluidine\; Oxidate_{colored}}$$

Note: Hydrogen peroxide is one of the products of glucose oxidation to glucolactone by glucose oxydase.

• is this homework?
– user4076
Mar 3 '14 at 19:04
• @Amaterasu Not really. If I remember correctly, this was/is a method for the photometric determination of glucose in blood. Mar 3 '14 at 19:57
• @KlausWarzecha ah, good to know!
– user4076
Mar 3 '14 at 20:02

## 1 Answer

The product most likely is 2-methylnitrobenzene (3), which means that the amino group ($\ce{-NH2}$) in o-toluidine (1) is oxidized to a nitro group ($\ce{-NO2}$). The oxidation proceeds via 2-methylnitrosobenzene (2).

The formation of 2-methylnitrobenzene can be detected photometrically at $\lambda$ = 400 nm, where the aniline does not absorb.