Could anybody describe which product is formed in the following reaction (o-Toluidine oxidation)?

$$\ce{H2O2 + o-Toluidine_{uncolored} - Peroxidase -> H2O + 1/2 O2 + o-Toluidine\; Oxidate_{colored}} $$

Note: Hydrogen peroxide is one of the products of glucose oxidation to glucolactone by glucose oxydase.

  • $\begingroup$ is this homework? $\endgroup$
    – user4076
    Mar 3 '14 at 19:04
  • $\begingroup$ @Amaterasu Not really. If I remember correctly, this was/is a method for the photometric determination of glucose in blood. $\endgroup$ Mar 3 '14 at 19:57
  • $\begingroup$ @KlausWarzecha ah, good to know! $\endgroup$
    – user4076
    Mar 3 '14 at 20:02

The product most likely is 2-methylnitrobenzene (3), which means that the amino group ($\ce{-NH2}$) in o-toluidine (1) is oxidized to a nitro group ($\ce{-NO2}$). The oxidation proceeds via 2-methylnitrosobenzene (2).

toluidine oxidation

The formation of 2-methylnitrobenzene can be detected photometrically at $\lambda$ = 400 nm, where the aniline does not absorb.


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