enter image description here

I understand till we get “f” And also why f is directly proportional to PH. But I don’t understand why f is multiplied in solubility product with solubility of salt of weak acid.

(Sorry for poor english) (couldn’t find link of pdf of this book online)

  • $\begingroup$ What is this book? $\endgroup$ – andselisk Jan 12 '18 at 16:42
  • $\begingroup$ 11th class ncert chemistry “acids bases and salts” $\endgroup$ – Fawad Jan 12 '18 at 16:49
  • $\begingroup$ The notations are very poorly picked. Upright "S" stands for both sulfur element and solubility, brackets "[]" are used both for concentrations and to enclose variables, the font makes it impossible to distinguish between { and (, and so on (and this is only from what you photocopied). I've never seen this book before, but I'd rather get something better than this. $\endgroup$ – andselisk Jan 12 '18 at 18:54

Notice that $f$ is equal to the maximum concentration of $\ce{M}$, which is unchanged as part of the acid-base equilibrium. On the other hand, the pH changes the concentration of the counterion in proportion to $f$. Therefore, the second term in the solubility product is scaled accordingly.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.