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All of these appeared to be correct. I’ve already counted their hydrogen and carbon number. Please help!

[enter image description here1]: https://i.stack.imgur.com/tnQvO.jpg

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    $\begingroup$ (D) is n-heptane only. So, it should be the answer. $\endgroup$
    – Arishta
    Jan 7 '18 at 6:44
  • $\begingroup$ If you were ever asked to count the total number of structural isomers of heptane, you will definitely count n-heptane as one of them. However, this question has explicitly drawn what "heptane" looks like (actually it's n-heptane), and then asks you to identify which of the following is NOT an isomer of "heptane". Clearly, option D is not an isomer of "heptane", rather "heptane" itself. Hence, D. $\endgroup$ Jan 7 '18 at 7:58
  • $\begingroup$ @GaurangTandon Is it because D’s vertical chain isn’t less than D’s horizontal chain. $\endgroup$
    – user28603
    Jan 8 '18 at 3:45
  • $\begingroup$ @user28603 It is a single unbroken carbon chain of seven atoms... $\endgroup$ Jan 8 '18 at 10:05
  • $\begingroup$ @GaurangTandon So you're saying that the structure drawn in D is the principle chain of Heptane. The structure that is above the question isn't the principle chain of Heptane. Am I right? $\endgroup$
    – user28603
    Jan 11 '18 at 5:22
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The structure in the question and option (D) are the same thing. Note that a branching as apparently seems is not a real branch on the principle chain that would give an isomer. Basically (D) is same as that given in the question.

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  • $\begingroup$ But a, b, c, d’s amounts of hydrocarbons are the same right? $\endgroup$
    – user28603
    Jan 7 '18 at 7:36
  • $\begingroup$ @user28603 I didn't get it.What do you mean by amount of hydrocarbons? $\endgroup$
    – Soham
    Jan 13 '18 at 17:05
  • $\begingroup$ Amount of Hydrogen and Carbon. $\endgroup$
    – user28603
    Jan 14 '18 at 23:05
  • $\begingroup$ @user28603 Yes. The amount is same as structural formula is similar. $\endgroup$
    – Soham
    Jan 15 '18 at 13:41
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The option d should be correct since the name of the compound is the same as the given in the question... They are homomers

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