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In the Oakwood reaction, i.e. $$\ce{RCOOH ->[NaOH + CaO] RH + Na2CO3},$$ is there any role or importance of $\ce{CaO}$, because it doesn't appear to be anywhere in the product.

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  • $\begingroup$ Sodium hydroxide plus calcium oxide forms soda lime. Its use purely handling convenience, it has a high surface area for reaction and is far less hygroscopic than solid sodium hydroxide powder. $\endgroup$ – Waylander Dec 26 '17 at 10:37
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Sodium hydroxide plus calcium oxide forms soda lime. Its use is mainly down to handling covenience as it is far less hygroscopic than powdered sodium hydroxide.

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    $\begingroup$ Well, now your comment is obsolete, also it would be good if answer was longer then comment ;) $\endgroup$ – Mithoron Dec 26 '17 at 15:32

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