# How can a methyl halide react by intramolecular SN2?

Out of the following, $\ce{CH3Br}$ doesn't react by which mechanism?

1. SN2
2. SN1
3. E2
4. Intramolecular SN2
5. E1

My textbook gives 2, 3 and 5 as the correct answers, which means it does react by 1 and 4.

But how can a methyl halide react by intramolecular SN2, without a nucleophile present in the molecule? There's just a leaving group ($\ce{-Br}$).