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In hydration of an alkene by oxymercuration-demercuration, for an asymetrical mercunium ion, the more substituted carbon atom is attacked by water.

Why is this the case? Since R groups are electron donating, it should make the more substituted carbon less electrophilic, also water would like to attack the carbon having less steric hindrance but the reverse is true.

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  • $\begingroup$ Did you find an answer about this question because i also have it . Thanks in advance. $\endgroup$ – ado sar Mar 15 at 15:51
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Using 1-methyl-1-cyclohexene as an example, the mercurinium ion is not symmetrical. If it were, the positive charge would all be on mercury. The ion is unsymmetrical with part of the positive charge on the more substituted carbon. Why this carbon? Follow Markovnikov's Rule: tertiary carbocations are more stable than secondary carbocations. This bias is manifested in the transition state permitting water to attack at the more substituted carbon. The addition is anti. I chose 1-methyl-1-cyclohexene as an example because adding a tertiary butyl group to the 4-position produces more subtle aspects of the reaction mechanism.

enter image description here

While structures 1 and 2 above are both tertiary alcohols, only alcohol 1 is formed. This selectivity is controlled not only by the anti-addition but also by the more favorable chair-like transition states (red arrows) over the boat-like transition states (blue arrows). These issues are provided in greater detail at http://ursula.chem.yale.edu/~chem220/chem220js/StudyAids.html#Mechanisms as PowerPoint and pdf files.

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  • $\begingroup$ What if an electron withdrawing group is present at one side of the double bond, will condition change or it will remain same? $\endgroup$ – Madhukesh Kumar Jan 26 '18 at 3:08
  • $\begingroup$ If the methyl group were a methyl ketone, then it would a more electron-deficient double bond and less reactive. If the mercurinium ion formed, my best guess is that the mercury would wind up at the alpha-position and water add at the beta-position. If this is the case, then the hydration should be catalytic in mercury (Cf. oxymercuration of alkynes). The product would be a beta-hydroxy ketone. $\endgroup$ – user55119 Jan 26 '18 at 3:24
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Oxymercuration is very regioselective and is a textbook example of reaction obeying Markovnikov's reaction. This phenomenon is explained by examining the three resonance structures of the mercurionium ion formed at the end of the first step during reaction. In one stage you will have a tertiary carbocation, which of course is a very reactive electrophile. The nucleophile will then attack the mercurinium ion. Therefore, the nucleophile attacks the more substituted carbon because it retains a more positive character than the lesser substituted carbon.

And about steric hinderance: oxymercuration is an anti-addition.

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