1
$\begingroup$

Is my proof valid for the formula of elevation in boiling point?

proof

By Clausius clayperon equation, $$\ln(P)=-\frac{∆H_v}{RT}+c$$ Differentiating, $$\frac{dP}{P}=\frac{∆H_v dT}{RT^2}$$ Approximating $dP\approx ∆P$ , $dT\approx ∆T$, $$\frac{∆P}{P}=\frac{∆H_v∆T}{RT^2}$$ Let $∆P=P_{solution}-∆P_{solvent}$ and $T^2\approx T_{boiling}^2$ also $∆T=$ Change in boiling point,

By the formula for relative lowering of vapour pressure, $\frac{∆P}{P}=mf_{solute}$ $$mf_{solute}=\frac{∆H_v∆T_{boiling}}{RT_{boiling,solvent}^2}$$ $$∆T=\Big(\frac{RT_b^2}{∆H_v}\Big)mf_{solute}$$ But i don't know how to proceed further, can anyone help?

The actual formula differs from mine as, $$∆T=\Big(\frac{RT_b^2}{∆H_v}\Big)molality_{solute}$$

$\endgroup$

closed as unclear what you're asking by Mithoron, jerepierre, airhuff, Tyberius, Jon Custer Nov 13 '17 at 20:52

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ I'm not sure that you can go further; is there a reason you expect to be able to do so? $\endgroup$ – a-cyclohexane-molecule Nov 13 '17 at 16:22
  • $\begingroup$ I updated the question @a-cyclohexane-molecule $\endgroup$ – neonpokharkar Nov 14 '17 at 7:04