# Where does the additional hydrogen in the Fischer depictions of glucopyranose come from?

My book shows this figure of Fischer formula of D-glucose:

I don't understand this figure, and I wonder why the upper carbon atoms in both the right and left formulas have 5 bonds.

And from where comes this hydrogen atom in the upper left side of the figure (attached to α-D-glucopyranose).

When turning D-glucose to Fischer formula, it seems there's an additional hydrogen atom, isn't it? Why and how does this happen?!!

Could someone explain how to get from the aldehyde form of glucose (the middle structure) to the β-D-Glucopyranose and the α-D-Glucopyranose?

The mechanism of ring-closure is also mentioned in sufficient detail on the corresponding Wikipedia page to which I hereby point you. Basically, the 5-hydroxy group attacks the $\ce{C=O}$ π system as a nucleophile. Proton transfer will lead to the cyclic product. (In actual aquaeous solution, the carbonyl oxygen will be protonated immediately from a nearby water molecule and one will also take away the hydroxy group’s excess proton, so the two are not the same.)