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I have recently completed an experiment with hydrogen peroxide (5%), 0.1M KI and 1M NaOH.

Is the sodium hydroxide a reactant or a catalyst in this experiment?

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closed as off-topic by Mithoron, bon, Jan, airhuff, Todd Minehardt Oct 22 '17 at 16:38

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In basic solution the half reactions are:

Reduction:

$\ce{H2O2 + 2 e- -> 2 OH-}$

Oxidation:

$\ce{I- + 6 OH- -> IO3- + 3 H2O + 6 e-}$

So the overall reaction is

$\ce{3 H2O2 + I- -> IO3- + 3 H2O}$

thus $\ce{OH-}$ is overall neither a reactant nor a product. Hence it is either a catalyst, an inhibitor, or a spectator ion.

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