I am not now nor have I ever been a chemist.
I'm practicing by drawing molecules in the Chemspider structure search tool. Today I drew buckminsterfullerene, in order also to test my 3D spatial awareness. I chose to draw the double bonds on the hexagonal rings only - the resulting symmetry making this the intuitive choice, I thought.
Chemspider recognised my sketch as C60 right enough, but in its own 3D rendering has the double bonds placed differently, with some in the pentagonal rings, so of course I run to Google to see what is up with that, and learn the following from Wikipedia :
C60 tends to avoid having double bonds in the pentagonal rings, which makes electron delocalization poor, and results in C60 not being "superaromatic".
So according to this my intuition was correct, but I guess Chemspider just has a different version stored for some reason?
Q0: Any guess as to WHY Chemspider has different configuration?
Q1: Is the extract above actually true? (If you can imagine for a moment a world where Wikipedia might not be 100% accurate and authoritative)
Q2: If so, why? As I said, the more maximally symmetric arrangement seems intuitive. I guess the charge of the mutually repelling (repulsive?) electrons would be more evenly distributed this way, and so this is how it would self-organise, like a soap bubble.
Q2: In the context of the extract, does electron delocalization being 'poor' mean that there is a lot of it (this is my instinct), or not so much?
Q3: Either way, why is the degree of delocalization contingent upon where the double bonds are? My first guess would be that the positively charged nuclei in the hexagons keep the electrons in a less vice-like grip than in the more tightly convex pentagons.
Q4: Are the bonds static? Once you have a C60 molecule with its bonds a certain way, do they stay that way, or do they jump about arbitrarily?
Q5: Does it matter? Does the geometry of the bonds affect the chemistry, or indeed physics, of C60 that much?
If your answer is 'go read a book/paper on C60' then that's fine, if you could recommend a good one for a beginner. There's a lot out there.