Relation of conductivity with electrode distance [closed]

Question

Conductivity is defined as the conduction of ions when the distance between the electrodes is 1 cm and length is 1 cm.
Say for instance we have a solution where the distance between the electrodes is 2 cm and its height is also 2 cm, what will be the resulting conductivity of the solution?

Answer 1

sigh... lifted out of Definitions section of wikipedia article on Conductivity (electrolytic)

Resistance, $R$, is proportional to the distance, $l$, between the electrodes and is inversely proportional to the cross-sectional area of the sample, $A$. Writing $\rho$ (rho) for the specific resistance (or resistivity),

$R={\frac {l}{A}}\rho$

In practice the conductivity cell is calibrated by using solutions of known specific resistance, $\rho^*$, so the quantities $l$ and $A$ need not be known precisely. If the resistance of the calibration solution is $R^*$, a cell-constant, $C$, is derived.

$ R^{*}=C\times \rho ^{*}$

The specific conductance (conductivity), $\kappa$ (kappa) is the reciprocal of the specific resistance.

$\kappa ={\frac {1}{\rho }}={\frac {C}{R}} $

So if $l_1 = 1 \text{ cm}$, $A_1 = 1 \text{ cm}^2$ but $l_2 = 2\text{ cm}$, $A_2 = 4 \text{ cm}^2$

$\kappa_1 ={\frac {C}{R}} $

$\kappa_2 ={\frac {2C}{R}} = 2\kappa_1 $