What are hybridisation states of each carbon atom in the following compounds?
- $\ce{CH2=C=O}$
- $\ce{CH3CH=CH2}$
- $\ce{(CH3)2CO}$
- $\ce{CH2=CHCN}$
- $\ce{C6H6}$
How do I find the hybridisation of the orbitals of the carbon atom in such compounds?
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Sign up to join this communityMy method for finding the hybridization of the orbitals of an atom in a molecule:
For hydrocarbons, if the carbon atom forms only σ bonds, the orbitals of it will be sp3 hybridised. If the carbon atom forms a π bond, its orbitals are sp2 hybridised. If the carbon atom forms two π bonds, its orbitals are sp hybridised.
Just apply the bond method which is the simplest and most effective. Count the number of bond pairs of central atoms excluding pi-bonds and the number Of lone pairs and match the corresponding hybridisation.