# Reverse reaction of acid dissociation [closed]

Consider an acid HA with Ka 10^-10 dissociating into its ions as

HA⇌H+ +A-

My question is-if we introduce solution of pH=3(let's say any weak acid or a buffer) and put ions of A- of 0.1M into it (using strong electrolyte),using expression for Ka(in this case we are operating reverse reaction so k will be reciprocal of Ka) we get concentration of HA to be 10^6 M.Although such a high concentration is theoretically not obtained (assume for my doubt to get clarified) my focus is on the following question (value of 10^6 from FORMULA only):- How is it CHEMICALLY CORRECT that concentration of products has become more than reactants?While dissociating we can make the argument that some acid is left undissociated so concentration decreases.But how does concentration INCREASE in reverse reaction and what is its chemical significance? Please help.

(I came across this doubt when I saw a question asking to calculate solubility of AgCN in buffer of pH=3 ksp=1.2×10^-15 and ka of hcn 4.8×10^-10.Solution implied concentration of hcn was much greater than cn from AgCN which confused me as explained above.)

## closed as unclear what you're asking by Mithoron, bon, Jon Custer, airhuff, JanOct 10 '17 at 16:28

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• Sure enough, $10^6\rm M$ screams nonsense, no matter how it came about. – Ivan Neretin Oct 9 '17 at 7:02
• Can you please write down what exactly you want to add to what? I recommend you also translate that into specific amounts of real chemicals. It will become very clear where you are going wrong then. – Karl Oct 9 '17 at 7:20