The ionic radii of $\ce{Ba^2+}$ and $\ce{O^2-}$ in barium oxide are $\pu{135pm}$ and $\pu{140pm}$, respectively. The ratio of the radius of $\ce{Ba^2+}$ to $\ce{O^2-}$ is approximately $0.964$.

According to the radius ratio rules the solid barium oxide should crystallise in a body-centered cubic type structure (like $\ce{CsCl}$).

Radius Ratio

But evidently the prototype structure is $\ce{NaCl}$ type.

What is the reason for this anomaly from general trend?

EDIT: I found that every alkaline earth metal oxides (Of the type $\ce{M_{alk.e}O}$) possesses rock salt (halite) structure but only $\ce{MgO}$ obeys the radius ratio rule (it has a radius ratio of about $0.64$ which is well between $0.414$ and $0.732$).

Certainly as we are going down the group the cationic radius is going to increase and so is the radius ratio.

  • 2
    $\begingroup$ The mentioned trend is but a crude generalization. $\endgroup$ Sep 27, 2017 at 15:13
  • $\begingroup$ Please elaborate.... $\endgroup$
    – Serotonin
    Sep 27, 2017 at 16:13
  • 3
    $\begingroup$ What's to elaborate? Tall guys play basketball, short guys play football; that's an empirical correlation. It is mostly true, but exceptions both ways are plenty. On the other hand, $(a+b)^2=a^2+2ab+b^2$; that's a law. Can it be broken? Not a chance. Well, your trend is not a law. $\endgroup$ Sep 27, 2017 at 17:17
  • 1
    $\begingroup$ The reason is basically that the crystal structure was measured and found to be the NaCl structure. Now good luck finding a reason. $\endgroup$
    – Jan
    Sep 28, 2017 at 9:42
  • 2
    $\begingroup$ @Serotonin Everything has a reason; it's just that you'll have to wait till someone figures out what the reason is... ;) $\endgroup$ Sep 29, 2017 at 10:03


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.