You're correct in saying that p-orbitals are identical, and it follows that the following configurations are the same:

You must only consider their relative alignments (i.e. their symmetry).
To consider your question, approach it using the Hückel method. The wavefunction of a molecular orbital is given as a linear combination of the atomic orbitals, which mathematically looks like:
\begin{equation} \tag{1}
\Psi = c_1\phi_1 + c_2\phi_2 + c_3\phi_3 + c_4\phi_4
\end{equation}
where $c_i$ is the coefficient of $\phi_i$ in the LCAO-MO picture. Using the Hückel method we build the secular determinant for the molecular orbitals (see here if you're unfamiliar with this):
\begin{equation} \tag{2}
\begin{vmatrix}
x & 1 & 0 & 0 \\
1 & x & 1 & 0 \\
0 & 1 & x & 1 \\
0 & 0 & 1 & x
\end{vmatrix}
= 0
\end{equation}
where $x$ is defined as
\begin{equation} \tag{3}
x = \frac{\alpha - E}{\beta}
\end{equation}
The expansion of the secular determinant is trivial and gives the following roots:
\begin{equation} \tag{4}
x = \pm 1.62 \hspace{0.5cm} \text{or} \hspace{0.5cm} x = \pm 0.62
\end{equation}
Since the 4x4 secular determinant is made from 4 atomic orbitals, it is mathematically restricted to have 4 solutions. Using Equation 3 one may rearrange these solutions to find the orbital energies in terms of $\alpha$ and $\beta$. These roots are actually the eigenvalues of the secular matrix $ \ \textbf{H} - E\textbf{S} \ $ used in the Hückel method. The corresponding eigenfunctions are the coefficients of the atomic orbitals in Equation 1. The molecular orbitals for butadiene are found to be:
\begin{align} \tag{5}
\Psi_a &= \phantom{-}0.372\phi_1 + 0.602\phi_2 + 0.602\phi_3 + 0.372\phi_4 &
E &= \alpha + 1.618 \beta \\
\Psi_b &= -0.602\phi_1 - 0.372\phi_2 + 0.372\phi_3 + 0.602\phi_4 &
E &= \alpha + 0.618 \beta \\
\Psi_c &= -0.602\phi_1 + 0.372\phi_2 + 0.372\phi_3 - 0.602\phi_4 &
E &= \alpha - 0.618 \beta \\
\Psi_d &= \phantom{-}0.372\phi_1 - 0.602\phi_2 + 0.602\phi_3 - 0.372\phi_4 &
E &= \alpha - 1.618 \beta
\end{align}
If you look closely at the signs of each coefficient, you can see that they correspond to the phases in the allowed molecular orbital configurations. The origin of this behaviour follows from the discrete nature of quantum mechanics. If we call the coefficients amplitudes of a sine wave fitted to the length of the molecule this is more clear:

There is no solution to our secular determinant which allows for orbital symmetry in the way which you queried. This is explained by the picture formed by the sine waves, along with the particle in a box model.
References:
P. Atkins & R. Friedman, Molecular Quantum Mechanics, Oxford University Press, Oxford, 5th edn., 2011.
https://chem.libretexts.org/