# why do we avoid the [AgCl] to calculate K? [closed]

why do we avoid the [AgCl] to calculate K?

## closed as off-topic by Jan, NotEvans., Pritt Balagopal, DSVA, MithoronSep 9 '17 at 13:01

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$\ce{AgCl}$ is a solid, and those are not included in the reaction quotient (or set to 1). It's handled e.g. here: