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Consider an equilibrium reaction with an aqueous solution $\ce{A(aq)}$ in equilibrium phase with gas: $$\ce{A(aq) + B(g) <=>[$K_\mathrm{eq}$] C(g)}$$ Would the equilibrium constant have aqueous solution $\ce{A(aq)}$ contributing to it?

In my opinion I think it would. Can anyone please correct me? Also, please help me find literature which explains equilibrium constant in details.

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    $\begingroup$ When a substance is distributed between two phases chemists define a partition coefficient. $\endgroup$
    – MaxW
    Sep 3, 2017 at 16:17

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  • If you are talking about a species dissolved in a aqueous solution then yes it would feature in the constant .
  • However if you are referring to the solvent itself then no it wouldn't feature in the constant this is because the concentration of the solvent is constant , as well as the fact that it is present on both sides of the equation since both reactants and products are dissolved in the same solvent
  • If you are referring to a partial pressure equillibrium constant , then a hybrid one will have to be created that has the partial pressure of the gases and the concentration of species that are not gases
  • Using a Kc value would mean simply taking the concentration of both the gases and the solutes , to end up with a constant , however solvents are excluded because the concentration of solvents is constant and is thereby thought as being absorbed in the eq constant itself
  • Derivation of the equilibrium constant requires probability and is quite lengthy so maybe you can check the video on khan academy that discusses the derivation
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  • $\begingroup$ I am referring to the solute and it is the concentration equilibrium constant,so It is factored in.If it is partial pressure equillibrium constant ,How would you state the pressure of the solute ? $\endgroup$ Sep 4, 2017 at 15:27
  • $\begingroup$ As I stated before it would be a hybrid constant , one that takes in the partial pressure of gases and the concentration of the solute , so you don't take the pressure or the solute but the concentration of it $\endgroup$
    – LM26
    Sep 6, 2017 at 20:07

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