# Are metal oxides thermodynamically more stable then fluorides? [closed]

I came across a statement that $\ce{PbO}$ is more stable then $\ce{PbF2}$. Now how can i justify that staement because fluorine being more electronegative and should form stronger bond with metals than oxygen.

## closed as too broad by Mithoron, bon, andselisk♦, Tyberius, airhuffSep 28 '17 at 18:32

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• You put $\ce{PbO}$ on a shelf and it will stay there forever without any change. Ditto for $\ce{PbF2}$. Now what does "more stable" really mean? – Ivan Neretin Aug 21 '17 at 15:23
• Stability obiously mean thermodynamic stability. PbO is thermodynamically more stable then PbF2 – Yogi Joshi Aug 21 '17 at 15:25
• This was not obvious at all, so you might want to edit your question to that effect. Also, do you have any numerical evidence to support your claim? – Ivan Neretin Aug 21 '17 at 15:37
• I read in a book n even i couldnt justify tht statement hence m askng are oxides more stable then fluorides? – Yogi Joshi Aug 21 '17 at 15:40
• "$\ce{PbO}$ is thermodynamically more stable then $\ce{PbF2}$" I don't think this statement has any meaning. You need to specify thermodynamically stable relative to what? The constituent elements? – Zhe Aug 21 '17 at 15:54