# Meisenheimer complex in Preparation of 2-Naphthol from 2-Naphthalenesulfonic acid

I'm trying to figure out the addition-elimination mechanism for the preparation of 2-naphthol from 2-naphthalenesulfonic acid. I know that the $\ce{SO3^2-}$ group is functioning as the leaving group, but I don't know how to draw the Meisenheimer complex.

I also can't find anything on the internet about the Meisenheimer complex of naphthalene, I tried to draw it, but this became too hard for me as there were too many resonance structures. Can someone please help?