# discover of the neutron, what happen to 2+ charge

James Chadwik found the neutron by shoot α rays to a Beralium foil. α rays are equal to the He²⁺ and he saw that particles without a charge is out from that. He understood the neutrons are those particles without the charge.

But my question is this.

This is the equation that the chadwik found.

Be + He²⁺= C +neutron

In this equation the left side has a 2+charge, but in right there is no any charge. So, What happen to the 2+ charge when this reaction occurs?

• For nuclear reactions, usually occurring at very high energies (compared with typical electron binding energies) one just ignores the electrons - they are going to do what they will do, and have zero impact on what the nucleons are doing. So, that would usually be written $^{9}Be (\alpha, n) ^{12}C$. The alpha was just a way to get an energetic-enough alpha to enter the nucleus and react. Aug 15 '17 at 15:36
• Electrons have no importance whatsoever in the reaction. Aug 15 '17 at 17:11
• When $\ce{He^{2+}}$ ions hit a beryllium target, then the target will become charged. However beryllium is an excellent conductor. So if you electrically ground the target then the charge will disparate. // You have to realize that energetic $\ce{He^{2+}}$ ions will leave a trail of ions as the $\ce{He^{2+}}$ travels through the beryllium. This isn't like a chemical reaction. Also remember that you got the $\ce{He^{2+}}$ ion by stripping off two electrons. Those electrons are floating around somewhere in the universe...
– MaxW
Aug 16 '17 at 3:27