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For using the Nernst equation

$$E = E_0 - \frac{RT}{nF}\ln\frac{[\ce{Red}]}{[\ce{Ox}]}$$

the concentrations of $\ce{Red}$ and $\ce{Ox}$ species are required. For the reaction

$$\ce{Cu+ + e- <=> Cu}$$

in which the $\ce{Red}$ part leaves the solution and has no concentration in the electrolyte. How is the Nernst equation used to calculate the potential at different stages when the reaction proceeds?

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closed as off-topic by Mithoron, airhuff, Todd Minehardt, Pritt Balagopal, paracetamol Aug 15 '17 at 9:01

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For a metal electrode immersed in a solution of its own salt, the concentration of the reduced form as a solid phase remains constant ($[\ce{M^0}] = \mathrm{const}$), therefore:

$$E = E_0 + \frac{RT}{nF}\ln[\ce{Ox}]$$

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