I have been able to slightly unpack the NMR spectrum for the nicotinic acid to understand the order of signals and what ones correspond to what protons but I am having a problem with why some of the signals produced a different number of peaks I can not explain. I understand how simple and complex spin-spin splitting works to an extent when producing a number of different types of groups such as, s, d, t, m, dd, dt and many others.

The spectrum below is one for nicotinic acid, and the peaks are in order of most downfield to least, signals for H on carbons 2, 6, 4 then 5.

Looking at the environment proton two is in it has no equivalent neighboring pairs so why is it producing a doublet?

Same goes for the proton at carbon six. Why is it producing a double of doublets when it only has one neighboring pair?

As for the signal for proton five that is simple to understand and it should produce a double of doublets because the neighboring protons are in-equivalent, but yet again this is still not the case for the splitting of the signal. The same for proton 4 which produces a double triplets.

Would some one be able to explain why this is occurring? enter image description here enter image description here

  • 2
    $\begingroup$ In an aromatic system, you can usually see couplings higher than 3J. $\endgroup$ Aug 4, 2017 at 12:57

1 Answer 1


First, a great source of information on this kind of problem is the website of Hans Reich at UW Madison, see e.g. here. Couplings can occur with protons at ring positions ortho, meta and para, with typical values of $\pu{7-9}$, $\pu{2-3}$ and $\pu{<1 Hz}$, respectively.

This is (roughly) the information I extracted from your spectrum:

  • $\pu{ 9.15 ppm, \space d, \space 1.5 Hz}$
  • $\pu{ 8.83 ppm,\space dd, \space 5 Hz, 1.5 Hz}$
  • $\pu{ 8.3 ppm, \space dt (apparent), \space 2 Hz (t), 8 Hz }$
  • $\pu{ 7.6 ppm, \space m (ddd), \space 5 Hz, 8 Hz, < 1 Hz}$

You should report the field at which the spectrum was acquired since otherwise the magnitude of the J couplings is ambiguous. Assuming that the largest J is $\pu{8 Hz}$ leads to the guess that it is a 400 MHz ($\ce{^1H}$) magnet. You should also report the solvent.

Second, your spectrum is very nice, showing great resolution. Compare for instance to this spectrum (also at 400 MHz but presumably much higher concentration - $\pu{100 mM}$). Either the concentration of the solvent and temperature may be reasons you obtain higher resolution, resolve very small couplings. The BMRB spectrum was acquired in D2O, pH 7.4, 298 K. Your spectrum was acquired perhaps in $\ce{H2O}$, and perhaps at low pH, resulting in protonation of the pyridine N, but probably not.

enter image description here

Based on the structure you expect 2 to have the weakest couplings to other H. It displays a small coupling, not easily quantifiable because you clipped the spectrum in the figure. 5 Is expected to be a doublet of doublets, with both couplings similar and large. It also displays a smaller third coupling. Therefore lets start by tentatively assigning 2 to the resonance at 9.15 ppm, and 5 to 7.6 ppm. The resonance at 8.3 ppm is an apparent doublet of triplets, the triplet splitting being small, 2 Hz, the larger 8 Hz matching up with that from 5, so this H is vicinal to 5. One of the smaller couplings is presumably to 2, the other to 6, explaining the apparent triplet multiplicity. The last resonance, at 8.8 ppm, has a coupling matching up to 5, and another smaller one to 4, so we assign this to 6. So, to summarize, here are the assignments:

  • $\pu{ 9.15 ppm, \space d, \space 1.5 Hz, \space }$ 2
  • $\pu{ 8.83 ppm,\space dd, \space 5 Hz, 1.5 Hz, \space }$ 6
  • $\pu{ 8.3 ppm, \space dt (apparent), \space 2 Hz (t), 8 Hz , \space }$ 4
  • $\pu{ 7.6 ppm, \space m (ddd), \space 5 Hz, 8 Hz, < 1 Hz, \space}$ 5

This matches your assignments and those in the BMRB. So this analysis explains the small coupling for 2. The simplest explanation: that's a meta coupling to 4. It does not explain the small coupling for 5, though. That might be a trans coupling to 2.

The magnetization transfer pathways between the assigned H can be verified by inspecting the $\ce{^1H-^1H}$ TOCSY available at the BMRB. In particular, there is no pathway between signals at 9.1 and 8.8 ppm.


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