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My thoughts on the problem: I am sort compound of sure C and D will not show geometric isomerism because of the same groups (H and H) attached. In compound A and B, suppose I swap the positions of H and Cl, I notice that it is not possible to obtain the new compound by rotation of the original one.
My doubt: Does that mean A and B show geometric isomerism. Also is my method, of interchanging the positions of H and Cl and checking if the same compound can be obtained by rotation, correct?

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    $\begingroup$ Related: Why is 1-ethylidene-4-methylcyclohexane chiral? $\endgroup$ – orthocresol Jul 30 '17 at 3:27
  • $\begingroup$ @orthocresol - Ohh ok. From that post I could conclude that D and C can not be correct answer. But I'm still confused between A and B. The solution given tells me the answer is only B. $\endgroup$ – NeshDude Aug 1 '17 at 5:19

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