Why can alkoxides leave in the $\text{E}_{\text{1cb}}$ mechanism? I refer to the mechanism below. I would think that the anion formed from the first step would be more stable than the alkoxide ion, because the charge on the alkoxide ion is intensified by the electron-donating alkyl group, making it less stable. Correct me if I am wrong.
image source: https://en.wikipedia.org/wiki/E1cB-elimination_reaction